/*some coins weigh 3 times can identify which one is conterfeitcounterfeit. */
#include#include using namespace std;/**store the input*/char left1[3][7]; //用数组的时候记得给数组确定范围 char right1[3][7];char result1[3][6]; bool isheavy(char); bool islight(char);int main(){ int n=0; scanf("%d",&n); while(n>0) { for(int i=0;i<3;i++) { cin>>left1[i]>>right1[i]>>result1[i]; } /**numerate all coins and judge if it is light or heavy*/ for(char c='a';c<='l';c++) { if(isheavy(c)) { printf("%c is the counterfeit and it is heavy",c); break; } if(islight(c)) { printf("%c is the counterfeit and it is light",c); break; } } n--; } system("PAUSE"); return EXIT_SUCCESS;}/**judge if the coin x satisfy the three weighings*/bool isheavy(char x){ for(int i=0;i<3;i++) { switch(result1[i][0]) { //if the coin x not exists in the down side, coin x is not the heavy, couterfeit one case 'd': if(strchr(right1[i],x)==NULL) return false; break; case 'u': if(strchr(left1[i],x)==NULL) return false; break; case 'e': if(strchr(left1[i],x)!=NULL||strchr(right1[i],x)!=NULL) return false; break; } } return true;}bool islight(char x){ for(int i=0;i<3;i++) { switch(result1[i][0]) { case 'd' : if(strchr(left1[i],x)==NULL) return false; break; case 'u' : if(strchr(right1[i],x)==NULL) return false; break; case 'e' : if(strchr(left1[i],x)!=NULL||strchr(right1[i],x)!=NULL) return false; break; } } return true;}
这次在字符串输入上花了很多时间。以后要注意c中对数组要给定其大小。
string a[0]形式的字符串数组需要用cin>>输入
char* a; cin>>a 是错误的形式，因为a是一个指针。
char* a; 用来定义动态数组
a=new char[5]; cin>>a;